Physics, asked by vanyatanay, 9 months ago

a truck start from rest and rolls down a hill with a constant acceleration. it travels a distance of 400m in 20seconds. find its acceleration. find the force acting on it if it's mass is 7tonnes

Answers

Answered by Tanujrao36
8

To Find :-

  • Acceleration

  • Force

Solution :-

GIVEN :-

  • Initial Velocity (u) = 0 m/s

  • Final Velocity (v) = \sf\dfrac{400}{20}=20 m/s

  • Time = 20 seconds

Explanation :-

\bf{\underline{\boxed{\red{a = \dfrac{v-u}{t}}}}}

{}

\implies\sf{a = \dfrac{20-0}{20}}

{}

\implies\sf{a = \dfrac{20}{20}}

{}

\implies\sf{a = 20 m/\ s^{2}}

{}

\bf{\underline{\boxed{\red{F = ma}}}}

{}

\implies\sf{F= 7000\times20}

{}

\implies\sf{F = 140000\:Newton}

{}

\bf{\underline{\underline{\green{Related\:Points\:-}}}}

★ Force is defined as the pull or push of an object.

★ Acceleration is the change in velocity per unit time

★ Acceleration and force are vector quantity

Answered by Anonymous
5

{  \huge{  \bold{\underline{ \underline{  \orange{Solution:-}}}}}}

Given:-

{\tt{Intial velocity (u) = 0 m/s}}  \\  \\

{\tt{final velocity (v) = \frac{400}{20} = 20}} \\  \\

{\tt{Time \: taken = 20}}  \\   \\

To Find :-

Acceleration

Force

{  \huge{  \bold{\underline{ \underline{  \red{Concept:-}}}}}}

a = acceleration

v= final velocity

u = intial velocity

◕ Force is that, which acting on a body changes or trains to change that state of raised for uniform motion of the body in a straight line .

◕ The change in the velocity of an object per unit time is measured by the physical quantity is called acceleration .

{  \huge{  \bold{\underline{ \underline{  \green{Formula \: used:-}}}}}}

\leadsto{\tt{\pink{a = \frac{v-u}{t}}}}  \\   \\

\leadsto{\tt{\pink{F = ma}}}  \\   \\

{  \huge{  \bold{\underline{ \underline{  \purple{Calculation:-}}}}}}

\leadsto{\tt{a = \frac{v-u}{t}}}  \\   \\

\leadsto{\tt{a = \frac{20 - 0}{20}}}  \\   \\

\leadsto{\tt{a = \cancel\frac{20}{20}}}  \\   \\

\leadsto{\tt{a = 1 m/s^2}}  \\   \\

\leadsto{\tt{NOW,}}  \\   \\

\leadsto{\tt{F = ma}}  \\   \\

\leadsto{\tt{F = ma}}  \\   \\

\leadsto{\tt{F = 7000× 20}}  \\   \\

\leadsto{\tt{F = 140000N}}  \\   \\

\longrightarrow\large\underline{\underline{\boxed{\mathtt{\color{purple}{F = 140000 N}}}}}{\color{teal}{\bigstar}}

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