a truck starting from rest and rolls down on a hill with a constant acceleration it travels a distance of 400 m in 20 seconds find its acceleration find the force acting on it of it is if it is mass is equal to 700 kg
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heya mate!!!
answer:
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The truck starts from rest, so initial velocity = 0
Distance travelled = 400 m
Time taken = 20 s
We know the equation of motion, S = ut + ½ at2
400 = 0 + ½ a * (20)2
a = 2 m/s2
Now, mass = 7 metric tonnes
= 7 * 1000
= 7000 kg
So force = mass * acceleration
F = 7000 * 2
=14000N
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hope it helps u !!!
#bebrainly
vasanthij97:
then i am very sorry cuz i didn't know to solve it
Answered by
0
heya...!!!
✔here is ua answer:
___________________________________________________________________________❤
Initial velocity of the truck, u = 0 m/s
Time taken, t = 20 s
Distance covered by the stone, s = 400 m
According to the second equation of motion:
s = ut + 1/ 2 at 2
We have
400 = 0 × 20 + 1 /2 × × (20) 2
⇒ 400 = 200
⇒ = 2 m/s2
Now, Force = mass × acceleration
⇒ F = 700 × 2 = 14000 N
hope it helps...!!❤
✔here is ua answer:
___________________________________________________________________________❤
Initial velocity of the truck, u = 0 m/s
Time taken, t = 20 s
Distance covered by the stone, s = 400 m
According to the second equation of motion:
s = ut + 1/ 2 at 2
We have
400 = 0 × 20 + 1 /2 × × (20) 2
⇒ 400 = 200
⇒ = 2 m/s2
Now, Force = mass × acceleration
⇒ F = 700 × 2 = 14000 N
hope it helps...!!❤
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