Question

a truck starts form rest and rolls down a hill with a constant acceleration, it travels a distance of 400 m in 20 s. find its acceleration.find the force acting on it if it's. mass is 7 tonnes (hint:1tonne=1000kh.)​

Answer 1

Answer:

Given data:

Mass of stone(m)=7000 kg

Distance(S)=400 meter

Time(t)=20 second

1) We have to find the acceleration of the truck

So from the equation of motion

$s = ut + \frac{1}{2} at {}^{2}$

whereu=0

S = ut + 1/2 at^2

a = 2 ×400 / 20 × 20

a = 2 m /. sec^2

2) Force acting on truck

So. ,from newton's 2

nd law of motion

F =ma

=7000×2

=14000N

=14kN

hope it will help you.....

Answer 2

Answer:

Given data:

Mass of stone(m)=7000 kg

Distance(S)=400 meter

Time(t)=20 second

1) We have to find the acceleration of the truck

So from the equation of motion

$s = ut + a \times \frac{1}{2} \times t ^{2}$

where u = 0

$s = a \times \frac{1}{2} \times {t}^{2}$

$a = \frac{2 \times s}{ {t}^{2} } \: \: \\ = \frac{2 \times 400}{20 \times 20} \\ \\ 2 \frac{m}{ {s}^{2} }$

2) Force acting on truck

So,from newton's 2 nd law of motion

F =ma=7000×2=14000N=14kN

Explanation:

I hope it's helpful to you plz mark me as a brainlist