Question

A truck starts from rest and accelerates uniformly at

Answer 1

Answer:

Hey mate please complete the question

Answer 2

Answer:

Initial velocity of the truck, u = 0

Acceleration, a = 2 m/s

2

Time, t = 10 s

As per the first equation of motion, final velocity is given as:

v = u + at

= 0 + 2 x 10 = 20 m/s

The final velocity of the truck and hence, of the stone is 20 m/s.

At t = 11 s, the horizontal component (vx) of velocity, in the absence of air resistance, remains unchanged, i.e.,

vx = 20 m/s

The vertical component (vy) of velocity of the stone is given by the first equation of motion as:

vy = u + ayt

Where, t = 11 - 10 = 1 s and ay = g = 10 m/s

2

vy = 0 + 10 x 1 = 10 m/s

The resultant velocity (v) of the stone is given as:

➡v = (vx^2+vx^2)^1/2

➡(20^2+10^2)^1/2

➡22.36 m/s.