Question

A truck starts from rest and has acceleration of 4 ms
2. A box is inside truck which is at 6 m from open end
of truck. The coefficient of friction between box and
truck is 0.1. How much time box will take to slip out of
truck?​

Answer 1

Explanation:

psufo force will be applied

Answer 2

The box will slip out of the truck in 2 seconds

Explanation:

Given:

The acceleration of truck is 4 m/s²

Box is 6 m from the inside end of the truck

The coefficient of friction between the truck and box is 0.1

To find out:

The time taken by the box to slip out of the truck

Solution:

Given that

a = 4 m/s²

s = 6 m

μ = 0.1

Let the mass of the box be m

When the truck is moving, in the frame of reference of truck a pseudo force ma will act on the block in the opposite direction

This force will cause the box to move

The frictional force in the opposite direction

= 0.1mg

Therefore, net force moving the box

$F=ma-0.1mg$

$\implies F=m(4-0.1\times 10)$

$\implies F=3m$ N

Net acceleration of the box

$a'=\frac{F}{m}=\frac{3m}{m}=3$ m/s²

The box starts from rest hence intial velocity = 0

Using the second equation of motion

$s=ut+\frac{1}{2}a't^2$

$6=0\times t+\frac{1}{2}\times 3\times t^2$

$\implies t^2=4$

$\implies t=2$ s

Hope this answer is helpful.

Know More:

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