A truck starts from rest and moves with a constant acceleration of 5.0 m/s2. (a) Find its speed and (b) distance traveled after 4.0 seconds
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Answered by
28
initial velocity=0m/s
acceleration=5m/s
time=4s
(i)speed acquired,
v=u+at
v=0+5×4
v=20m/s
(ii)distance travelled,
s=ut+1/2at2
s=0×4+1/2×5×4^2
s=5/2×4×4
s=5×8
s=40m.
acceleration=5m/s
time=4s
(i)speed acquired,
v=u+at
v=0+5×4
v=20m/s
(ii)distance travelled,
s=ut+1/2at2
s=0×4+1/2×5×4^2
s=5/2×4×4
s=5×8
s=40m.
Answered by
15
Explanation:
Initial speed of the truck, u = 0 (at rest)
Acceleration of the truck,
Time, t = 4 s
1. Let v is the final speed of the truck. Using the first equation of motion to find it as :
v = 20 m/s
2. Let s is the distance covered by the truck. It is given by :
s = 40 meters
Hence, this is the required solution.
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