a truck starts from rest and roll down a hill it travels a distance of 400m in 20s find its acceleration. find thr force acting on it if it's mass is 7 tonnes.
Answers
Explanation:
Initial velocity (u) = 0
Distance travelled (s) = 400 m
Time taken (t) = 20 s
Find out
The force acting on it if its mass is 7 metric tons
Solution
1 metric ton = 1000 kg
7 metric ton = 7 × 1000 = 7000 kg
∴ Mass (m) = 7000 kg
We know the formula
s
=
u
t
+
1
2
a
t
2
Substitute the given parameters in the above equation
400 = 0 + ½ a (20)2
400 = a × 400/2
400 = 200 × a
a = 2 m/s2
Acceleration is equal to 2 m/s2
Force (F) = Mass (m) × Acceleration (a)
Substitute the values of mass and acceleration in the above equation, we get
F = 7000 × 2
F = 14000 N
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Answer: Acceleration = 2m/s^2, Force =
Explanation:
Given: u = 0 m/s s = 400m t = 20 sec
Taking 2nd equation of motion:
s = ut + 1/2at^2
400 = 0*20 + 1/2(a*20^2) => 0 + 1/2*a*400 => 200a
Therefore, a = 400/200 = 2 m/s^2
We know, f = ma
m = 7 tonnes or 7000 kg
a = 2 m/s^2
Therefore, f = 7000*2 => f = 14000 N