A truck starts from rest and rolles down a hill with constant acceleration it travels a distance of 400m in 2sec. find the acceleration find the force acting on it. if it's mass 7 tanel
Answers
Explanation:
u=0
t=2s
s=400m
s=ut+1/2at^2
400=0*2+1/2*a*(2)^2
400=0+1/2*4a
400=2a
a=200m/s^2
f=m*a
f=7000*200(1 ton =1000kg)
f=1400000 Newton
Correct Question:
A truck starts from rest and rolles down a hill with constant acceleration it travels a distance of 400m in 2sec. find the acceleration find the force acting on it. If it's mass 7 tonnes.
Answer:
a = 2 m/s² and F = 14000 N
Explanation:
Given that a truck starts from rest and rolles down a hill with constant acceleration it travels a distance of 400m in 2sec and it's mass is 7 tonnes.
From above we can write,
- Initial velocity of the truck (u) = 0 m/s
- Distance covered by the truck (s) = 400 m
- Time taken (t) = 20 s
- Mass (m) = 7 tonnes = 7000 kg
Now,
s = ut + 1/2at²
Substitute the values,
→ 400 = (0)20 + 1/2 × a × (20)²
→ 400 = 0 + 400a/2
→ 400 = 200a
→ a = 2
Therefore, the acceleration of the truck is 2 m/s².
Now,
Force is defined as the product of mass and acceleration.
Force = mass × acceleration
Substitute the values,
→ F = 7000 × 2
→ F = 14000
Therefore, the force acting on it is 14000 N.