Question

A truck starts from rest and rolls down a hill with a constant acceleration it travels a distance of 400m in 20s.Find accelerating. Find force if mass is 7metric tons

Answer 1

Answer:

2,14×10^6N

Explanation:

This is so easy we get by the formulae s=ut+1/2at^2

Answer 2

✬ Acceleration = 2 m/s² ✬

✬ Force = 14000 N ✬

Explanation:

Given:

• A truck starts from rest (u) = 0
• Distance (s) covered = 400 m
• Time (t) = 20 seconds
• Mass (m) = 7 metric tonnes.

To Find:

• What is acceleration (a) = ?
• What is force required (F) = ?

Formula to be used:

• Newton's second law of motion S = ut + 1/2at²

• Force (F) = Mass(m) x Acceleration (a)

Solution: Using second law of motion we can find the acceleration of the truck.

$\implies{\rm }$ S = ut + 1/2at²

$\implies{\rm }$ 400 = 0 x 20 + 1/2 x a x (20)²

$\implies{\rm }$ 400 = 0 + 1/2 x a x 400

$\implies{\rm }$ 400 = 0 + 200a

$\implies{\rm }$ 400 = 200a

$\implies{\rm }$ 400/200 = a

$\implies{\rm }$ 2 ms² = a

Hence, The acceleration of the truck is 2 m/s²

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Since,

• 1 tonne = 1000 kg so
• 7 tonnes = 7 x 1000 = 7000 kg

Now using F = ma we can find the force→

$\implies{\rm }$ Force = 7000 x 2

$\implies{\rm }$ Force = 14000 Newtons

Hence, The force will be 14000 N.

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★ Other laws of motion are ★

➬ V = u + at

➬ V² = u² + 2as

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★ Acceleration ➬ The change in the velocity of the body with time.

★ Distance ➬ The length of actual path which is covered by a body between its initial and final position.