A truck starts from rest and rolls down a hill with a constant accerelation .It travels a distance of 400m in 20 s .Find it's accerelation.Find the force acting on it if it's mass is 7 tonnes
Answers
Answered by
2
PLS MARK BRAINLIAST
Explanation:
s=1/2at^2
400=1/2×a×(20)^2
a=2ms^-2
F=ma
=700×2
1400N
Answered by
2
Answer:
a = 2 m/s^2 and F= 14000N
Explanation:
Given-
u = 0
s = 400m
t = 20s
m = 7 tonnes = 7*1000 kg = 7000 kg
a = ?
F = ?
By 2nd law of motion
s = UT + 1/2 at^2
400 = 0* 20 + 1/2 * a * 20*20
400 = 1/2*400 *a
400 = 200 * a
a = 400/200
a = 2 m/s^2
F = ma
F = 7000*2
F = 14000N
Hope it helps.
Similar questions