Question

A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400 m in 20 seconds. Find it's acceleration. Find the force acting on it if it's mass is 7 metric tonnes. *​

Answer 1

${\rm{\red{\underline{\underline{\huge{Answer}}}}}}$

Given :

• Initial velocity (u) = 0 m/s

• Time (t) = 20 seconds

• Distance (s) = 400 m

•Mass (m) = 7 metric tonnes

To find :

Acceleration

Force acting on it

According to the question,

By using Newton's second equation of motion we will calculate acceleration,

$\star \: \boxed {\mathsf \pink{s = ut + \frac{1}{2} {at}^{2} }}$

$\implies\sf{400 = 0 \times 20 + \frac{1}{2} \times a \times ( {20)}^{2} }$

$\implies \sf{400 = 0 + \frac{1}{2} \times a \times 400 }$

$\implies \sf{400 =a \times 200}$

$\implies \sf{a = \cancel\frac{400}{200} {}^{ \: \: 2} }$

$\implies \sf{a = 2 \: {ms}^{ 2} } \red\bigstar$

So,the acceleration is 2 m/s²..

Now we will calculate the force applied,

$\star \boxed{ \sf \pink{F = ma}}$

°.° 1 metric tonnes = 1000 kg

.°. 7 metric tonnes = 7 × 1000

$\implies\sf{7 \times 1000 \times 2}$

$\implies \sf{14000 \: N} \pink \bigstar$

So,the force is 14000 N..

Here,

• N stands for Newton
• F stands for Force
• m stands for Mass
• a stands for Acceleration
• u stand for Initial velocity
• t stands for Time

Answer 2

Answer:

{\rm{\red{\underline{\underline{\huge{Answer}}}}}}

Answer

Given :

• Initial velocity (u) = 0 m/s

• Time (t) = 20 seconds

• Distance (s) = 400 m

•Mass (m) = 7 metric tonnes

To find :

Acceleration

Force acting on it

According to the question,

By using Newton's second equation of motion we will calculate acceleration,

\star \: \boxed {\mathsf \pink{s = ut + \frac{1}{2} {at}^{2} }}⋆

s=ut+

2

1

at

2

\implies\sf{400 = 0 \times 20 + \frac{1}{2} \times a \times ( {20)}^{2} }⟹400=0×20+

2

1

×a×(20)

2

\implies \sf{400 = 0 + \frac{1}{2} \times a \times 400 }⟹400=0+

2

1

×a×400

\implies \sf{400 =a \times 200}⟹400=a×200

\implies \sf{a = \cancel\frac{400}{200} {}^{ \: \: 2} }⟹a=

200

400

2

\implies \sf{a = 2 \: {ms}^{ 2} } \red\bigstar⟹a=2ms

2

★

So,the acceleration is 2 m/s²..

Now we will calculate the force applied,

\star \boxed{ \sf \pink{F = ma}}⋆

F=ma

°.° 1 metric tonnes = 1000 kg

.°. 7 metric tonnes = 7 × 1000

\implies\sf{7 \times 1000 \times 2}⟹7×1000×2

\implies \sf{14000 \: N} \pink \bigstar⟹14000N★

So,the force is 14000 N..

Here,

N stands for Newton

F stands for Force

m stands for Mass

a stands for Acceleration

u stand for Initial velocity

t stands for Time