A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of
400m in 20s. Find its acceleration.
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Answered by
0
Answer:
Given data:
Mass of stone(m)=7000 kg
Distance(S)=400 meter
Time(t)=20 second
1) We have to find the acceleration of the truck
So from the equation of motion S=ut+
2
1
a×t
2
, whereu=0
S=
2
1
a×t
2
a=
t
2
2×S
=
20×20
2×400
=2
sec
2
m
2) Force acting on truck
So,from newton's 2
nd
law of motion
F
=ma=7000×2=14000N=14kN
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Answered by
1
Let the initial velocity (u) be 0 m/s since train starts from rest, distance travelled (s) be 400 m and time taken (t) to travel s be 20 s. Let the acceleration be a m/s^2.
We have the formula s = ut + (1/2) at^2
On solving it.. We get
a = 2 m/s^2
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