a truck starts from rest and Rolls down a Hill with a constant acceleration it travels a distance of 400 m in 20 seconds find its acceleration find the force acting on it if its mass is 7000kg
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Answered by
11
The truck starts from rest, so initial velocity = 0
Distance travelled = 400 m
Time taken = 20 s
We know the equation of motion, S = ut + ½ at2
400 = 0 + ½ a * (20)2
a = 2 m/s2
Now, mass = 7 metric tonnes
= 7 * 1000
= 7000 kg
So force = mass * acceleration
F = 7000 * 2
= 14000 N
Distance travelled = 400 m
Time taken = 20 s
We know the equation of motion, S = ut + ½ at2
400 = 0 + ½ a * (20)2
a = 2 m/s2
Now, mass = 7 metric tonnes
= 7 * 1000
= 7000 kg
So force = mass * acceleration
F = 7000 * 2
= 14000 N
Answered by
6
Given,
u = 0
s= 400 m
t= 20 sec
As we know that,
s = ut+(1/2)at²
By implying values, we get
⇒400 = (1/2) a×(20)²
⇒800 = 400 a
⇒a = 2 m/s²
F = ma = 7000×2 = 14000 N
u = 0
s= 400 m
t= 20 sec
As we know that,
s = ut+(1/2)at²
By implying values, we get
⇒400 = (1/2) a×(20)²
⇒800 = 400 a
⇒a = 2 m/s²
F = ma = 7000×2 = 14000 N
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