A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400m in 20 sec. Find its acceleration. Find the force acting on it if its mass is 7 tonnes?
Answers
Answered by
3
acceleration is = to m/s ^2
and f=ma
f=7*10^3(approx.)
and f=ma
f=7*10^3(approx.)
Answered by
5
Hey dear here is your answer!!!!
Given:-
S= 400 m
T= 20 second
a= ?
u=0
S= ut+1/2 at^2
400= 0+400a
a= 1m/s^2
Convert 1 tonne to kg
1 tonne = 907.185 kg
7 tonne = 7 × 907.185 kg
7 tonne = 6350.293 kg
Force = m × a
Force = 6350.293× 1
Force = 6350.293 N
Hope it helps u dear...
Given:-
S= 400 m
T= 20 second
a= ?
u=0
S= ut+1/2 at^2
400= 0+400a
a= 1m/s^2
Convert 1 tonne to kg
1 tonne = 907.185 kg
7 tonne = 7 × 907.185 kg
7 tonne = 6350.293 kg
Force = m × a
Force = 6350.293× 1
Force = 6350.293 N
Hope it helps u dear...
helpme10:
Thanks for marking ..
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