A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400m in 20s. Find the acceleration. Find the force acting on it if its mass is 7 tonnes. (Hint: 1 tonne = 1000 kg.)
Answers
Answer:
a=2m/s^2 and F=14000N
Step-by-step explanation:
Initial velocity of the truck, u=0
Distance covered by the truck, s=400 m
Time taken to cover that distance, t=20 s
Let the acceleration of the truck be a
s=ut+ 1/2at^2
400=(0)20+ 1/2a(20)^2
a=2 m/s ^2
Mass of the truck M=7 tonnes=7000 kg
(∵1 tonne=1000 kg)
F=Ma=7000×2 =14000 N
Thus the acceleration of the truck is 2 m/s^2 and the force acting on it is 14000N.
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Answer:
Given parameters
Initial velocity (u) = 0
Distance travelled (s) = 400 m
Time taken (t) = 20 s
Find out
The force acting on it if its mass is 7 metric tons
Solution
1 metric ton = 1000 kg
7 metric ton = 7 × 1000 = 7000 kg
∴ Mass (m) = 7000 kg
We know the formula
s= ut +1/2 at^2
Substitute the given parameters in the above equation
400 = 0 + ½ a (20)2
400 = a × 400/2
400 = 200 × a
a = 2 m/s2
Acceleration is equal to 2 m/s2
Force (F) = Mass (m) × Acceleration (a)
Substitute the values of mass and acceleration in the above equation, we get
F = 7000 × 2
F = 14000 N