a truck starts from rest and Rolls down a hill with a constant acceleration it travels a distance of 400 m in 20 second find its acceleration find the force acting on it if the mass of the truck is 7 metric ton
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Given, Initial velocity of truck (u) =0 (Since, truck starts from rest)
Distance travelled, s = 400 m
Time (t) = 20 s
Acceleration (a) = ?
We know that,
NOTE:- (Check this attachment)
Force acting upon truck:
Given mass of truck = 7 ton = 7 X 1000 kg = 7000 kg
We know that, force, P = m x a
Therefore, P = 7000 kg x 2 m s - 2
Or, P = 14000 Newton
Thus, Acceleration = 2 m s - 2 and force acting upon truck in the given condition = 14000 N
Distance travelled, s = 400 m
Time (t) = 20 s
Acceleration (a) = ?
We know that,
NOTE:- (Check this attachment)
Force acting upon truck:
Given mass of truck = 7 ton = 7 X 1000 kg = 7000 kg
We know that, force, P = m x a
Therefore, P = 7000 kg x 2 m s - 2
Or, P = 14000 Newton
Thus, Acceleration = 2 m s - 2 and force acting upon truck in the given condition = 14000 N
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5
☺ Hello mate__ ❤
◾◾here is your answer...
u = 0 m/s
t = 20 s
s = 400 m
According to the second equation of motion:
s = ut + 1/2 at^2
400 = 0 + 1/2 × a × (20)^2
a = (400 × 2 )/400 = 2m/s^2
7 metric tons = 7000 kg
Now,
Force = mass × acceleration
⇒ F= 7000 × 2 = 14000 N
I hope, this will help you.
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
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