a truck starts from rest and Rolls down a hill with a constant acceleration it travels a distance of 400 m in 20 second find its acceleration find the force acting on it if its mass is 7 tonnes (1 tonne=1000 kg)
Answers
Answered by
8
It came in my exam
Here it your solution
Since it starts from rest so u = 0
Time = 20sec
S= 400
Apply
S= ut + 1/2 a tt
hence
400 = 0*20+1/2*(20)(20)
400 = 200a
a = 2 m/ s
we know F = ma
force = 70000*2
= 14000N
Here it your solution
Since it starts from rest so u = 0
Time = 20sec
S= 400
Apply
S= ut + 1/2 a tt
hence
400 = 0*20+1/2*(20)(20)
400 = 200a
a = 2 m/ s
we know F = ma
force = 70000*2
= 14000N
Answered by
4
☺ Hello mate__ ❤
◾◾here is your answer...
u = 0 m/s
t = 20 s
s = 400 m
According to the second equation of motion:
s = ut + 1/2 at^2
400 = 0 + 1/2 × a × (20)^2
a = (400 × 2 )/400 = 2m/s^2
7 metric tons = 7000 kg
Now,
Force = mass × acceleration
⇒ F= 7000 × 2 = 14000 N
I hope, this will help you.
Thank you______❤
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