Question

A truck starts from rest and rolls down hill with constant acceleration.It travels a distance of 400m in 20sec.Find its acceleration.Find the force acting on it if its mass is 7 metric tonnes

Answer 1

u=0m/s
s=400m
t=20s
m=7tonnes
=7×1000 1tonne=1000
=7000
s=ut+1/2at 2
400 =0×20+1/2×a×20 2
400 =1/2×400
400 = 200a
a=400/200
a=2m/s
F=ma
=7000×2
=14000N
hope ut helps y☺☺☺

Answer 2

$\textbf{Solution}$

Given, Initial velocity of truck (u) = 0 (Since, truck starts from rest) .

Distance travelled, s = 400 m

Time (t) = 20 s

Acceleration (a) = ?

As we know that

$S = ut + \frac{1}{2} a {t}^{2} \\ \\ Putting \: the \: values \: we \: get \\ \\ 400 = (0 \times 20) + \frac{1}{2} \times a \times 20 \times 20 \\ \\ 400 = 0 + 200a \\ \\ 400 = 200a \\ \\ \frac{400}{200} = a \\ \\ 2m/ {s}^{2} = a$


Given mass of truck = 7 ton

=> 7 x 1000 kg = 7000 kg {1 ton = 1000kg}


We know that, force, P=m × a

where m is mass and a is acceleration

Therefore, 

P =7000kg ×2m/s^2

Or, P = 14000 Newton


Thanks

Have a colossal day ahead

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