A truck starts from rest and rolls downs a hill with a constant acceleration . It travels a distance of 400 m in 20 s . Find it's acceleration . Find the force acting on it if it mass is 7 Tonnes
Answers
Answer:
Initial velocity of the truck ,u=0
Distance covered by the truck, s=400m
Time taken to cover that distance ,t=20s
Let the acceleration of the truck be a
s=ut+
2
1
at
2
400=(0)20+
2
1
a(20)
2
a=2m/s
2
Mass of the truck M=7tonnes=7000kg (∴1tonne=1000kg)
F=Ma=7000×2=14000N
Answer: 14000 N
Given parameters
Initial velocity (u) = 0
Distance travelled (s) = 400 m
Time taken (t) = 20 s
Find out
The force acting on it if its mass is 7 metric tons
Solution
1 metric ton = 1000 kg
7 metric ton = 7 × 1000 = 7000 kg
∴ Mass (m) = 7000 kg
We know the formula
\(s = ut + \frac{1}{2}at^{2}\)
Substitute the given parameters in the above equation
400 = 0 + ½ a (20)2
400 = a × 400/2
400 = 200 × a
a = 2 m/s2
Acceleration is equal to 2 m/s2
Force (F) = Mass (m) × Acceleration (a)
Substitute the values of mass and acceleration in the above equation, we get
F = 7000 × 2
F = 14000 N
Answer
The force acting on it if its mass is 7 metric tons is 14000 N
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