A truck starts from rest moves with a uniform acceleration of 0.5 m per second square for 2 minutes calculate the speed acquired and the distance covered
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v=u+at u=0 a=0.5 t=2minute first change time into second that become 120 sec put it in formula v=0+0.5×120 =60M/S answer
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the truck start from rest, so initial velocity= 0
distance travelled= 400m
time taken =20s
we know the equation of motion,
S= ut + 1/2a *(20)2
a= 2m/s
now, mass =7 metric tonnes
= 7* 1000
=7000 kg
so force =mass* acceleration
F =7000* 2
= 14000 N
distance travelled= 400m
time taken =20s
we know the equation of motion,
S= ut + 1/2a *(20)2
a= 2m/s
now, mass =7 metric tonnes
= 7* 1000
=7000 kg
so force =mass* acceleration
F =7000* 2
= 14000 N
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