Question

A truck starts moving with an initial velocity of 36km/h. How much distance will it cover in 1 minute if it moves with a uniform acceleration of 1m/s2?

Answer 1

First convert km/hr in to m/s. 
36 X 5/18= 10 m/s
Then use the equation of mition,
s=ut+1/2at^2
s=10 X 60+ 1/2 X 1 X 60 X 60
s= 600+1800
s=2400m

Answer 2

So; HERE,
Initial Velocity (u) = 36km/h
Acceleration (a) =
$\frac{1m}{ {s}^{2} }$
Time (t) = 1 min
Now, we can easily get that how much distance it will cover, by:

$s = ut + \frac{1}{2} a {t}^{2} \\ (on \: putting \: the \: values \: we \: get) \\ = > s = \frac{36km}{hr} \times 1min + \frac{1}{2} \times \frac{1m}{ {s}^{2} } \times ( {1min})^{2} \\ = > s = \frac{5m}{s} \times 60s + \frac{1}{2} \times \frac{1m}{ {s}^{2} } \times 3600 {s}^{2} \\ = > s = 300m + 1800m \\ = > s = 2100m$
Therefore, the truck will travel 2100m(2.1km) in such circumstances.

THERE YOU GO!!!.....