Question

A truck starts rest rolls down a hill with costant acceleration it travels a distance of 400m in 20s find its acceleration

Answer 1

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Answer 2

$\huge\underline\mathrm\red{GivEn:-}$

⭐ Initial Velocity (u) of truck is 0.

⭐ Distance(s) of truck is 400m

⭐ Time(t) of truck is 20sec

$\huge\underline\mathrm\red{To\: Find}$

⭐ Find the acceleration =?

$\huge\underline\mathrm\red{SoLutioN:-}$

To find the acceleration, we use the 2nd equation of motion

$\implies$ S = ut + $\large{\sf {\frac{1}{2}}}$ at²

$\implies$ 400 = 0 x 20 + $\large{\sf {\frac{1}{2}}}$ a(20)²

$\implies$ 400 = $\large{\sf {\frac{1}{2}}}$ a x 400

$\implies$ 400 = a x 200

$\implies$ a = $\large{\sf {\frac{400}{200}}}$

$\implies$ a = 2 m/s²

Thus, the acceleration of truck is 2 m/s²

$\huge\underline\mathrm\red{ThAnKs...}$