Question

a truck starts to move from rest against the acceleration of 3 metre per second square in 5 seconds calculate the final velocity and distance covered by the truck​

Answer 1

Answer:

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Answer 2

u=0

a= -3m/s2

t=5s

from 1st equation of motion,

v=u+at

v= o+ (-3×5)

v= 0+ -15

v= -15m/s

from 3rd equation of motion

v^2-u^2=2as

(-15^2)-0^2=2×-3×s

-125-0=-6s

-125=-6s

125=6s

s=125/6

s=20.8 m