Question

A truck starts to move from rest. If it gains the acceleration of
3m s2 in 5 sec, calculate the final velocity and distance covered by
the truck. ​

Answer 1

Explanation:

Given: acceleration(a) = 4 m/s 2 , time(t) = 5 sec, and vo = initial speed = 0

We’ll use this formula::

Distance(d)=vo⋅t+1/2⋅a⋅t2

d=0⋅5+1/2⋅4⋅52

d=1/2⋅4⋅52

d = 50 meters

>>>>>>>> 50 meters

To find final velocity use this formula: vf = final velocity

v2f=v2o+2⋅a⋅d

v2f=02+2⋅4⋅50

v2f=400

vf = 20 m/sec

>>>>>>> 20 m/sec