Question

A truck traveling with an initial velocity of 93.6 m/s comes to a stop in 2.87 secs. What is the acceleration of the truck?

Answer 1

Answer:

APply there a= change in velocity by time taken

here initially velocity is 93.6 and then it has been stated that it stops means final velocity becomes 0...And time taken by the body is 2.87

So a= (v-u)/t

U will get ur answer

Explanation:

Hope u UNDERSTOOD it well and MARK it as BRAINLIST

Answer 2

Explanation:

let,

u = initial velocity = 93.6 m/sec

v = final velocity = 0 m/sec

t= time taken = 2.87 sec

a=?

$by \: kinematical \: equation..... \\ \\ v = u + at \\ \\ 0 = 93.6 + a(2.87) \\ \\ 2.87a = - 93.6 \\ \\ a = \frac{ - 93.6}{2.87} \\ \\ a = - 32.6 \: \frac{m}{ {sec}^{2} } ........$

hope it helps.......✌✌