Question

A TRUCK TRAVELLING AT 54 KM/H IS SLOW DOWN TO 36 KM/H IN 10 SEC.FIND THE RETARDATION

Answer 1

$Hey\:There$‼

We have,
Initial velocity, u = 54 m/s
= ( 54 × 5/18 ) m/s
= 15 m/s

Final velocity, v = 36 m/s
= ( 36 × 5/18 ) m/s
= 10 m/s

Time, t = 10 sec

We know that,
Acceleration, a = ( v – u ) / t
= ( 10 – 15 ) / 10
= – 5 / 10
= – 1 / 2
= – 0.5 m/s²



So, retardation = 0.5 m/s²

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Answer 2

Answer:

Retardation is basically negative acceleration

so; retardation = v-u/t

initial velocity (u) = 54km/h

we will change it to m/s

1 km = 1000m

1 h = 60× 60 seconds

Therefore, 54×1000÷60×60 = 15 m/s

final velocity (v) = 36km/h = 36×1000÷60×60 = 10m/s

time= 10 sec

retardation = v-u / t

= 10-15/10 = -5/10 = -0.5 m/s

Explanation:

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