Science, asked by Vaibhav500, 11 days ago

A truck travelling at 54 km/h is slow down to 36 km/h in 10 sec. Find the retardation​

Answers

Answered by prabinkumarbehera
0

Answer:

Initial velocity = 54m/s

Final velocity = 36m/s

Acceleration = Final velocity - Initial velocity/time

Time given = 10 sec

Acceleration = 36 m/s - 54 m/s / 10 sec

Acceleration = -18/10

Acceleration = -1.8

Explanation:

The truck is travelling with a initial velocity of V=54m/s.

The truck is travelling with a final velocity of u=36m/s.

Acceleration=V-U/T.

Given time =10s.

so. 36-54/10

=-18/10

=-1.8

So. the retardation is 1.8 negative.

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Answered by pareshbali
0

Answer:

a= -4.4m/sec square answer, hence we can state the retardation is 4.4m/sec square. it means truck is slowing down at a rate of 4.4m per second

Explanation:

in this initial velocity u = 54km/h

final velocity v = 36km/h

formula we will apply here

v= u +at. here a is acceleration or retardation, and t is time

in given question velocity is given in km/h time is in seconds. (10 sec)

converting velocity from km/h to m/s

54km/h = 15m/sec ( multiply it with 5/18)

36km/h = 10m/sec

now putting values in the formula

v= u+at

10=54+ 10a

10-54= 10a

-44=10a

a= -4.4m/sec square answer

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