Question

a truck travelling at 54 km/h is slow down to 36 km per hour in 10 seconds find the retardation​

Answer 1

Answer:

Retardation  = 0.5m/s^2

Explanation:

Given,

Initial Velocity(u) = 54km/h

$=54\times \dfrac{5}{18}m/s$

Initial Velocity(u) = 15m/s

Final Velocity(v) = 36km/h

$=36\times \dfrac{5}{18}m/s$

Final Velocity(v)  = 10 m/s

time = 10s

To Find :-

Retardation(-a)

Formula Required :-

$a=\dfrac{v-u}{t}$

Solution :-

$a=\dfrac{10-15}{10}$

$=\dfrac{-5}{10}$

$=\dfrac{-1}{2}$

a = -0.5 m/s^2

Multiplying with '-' on both sides :-

-a = 0.5 m/s^2

Retardation = -a = 0.5m/s^2

Know More :-

1) v = u + at

2) s = ut + 1/2 at²

3) s = vt - 1/2at²

4) a = v - u/t

5) v²-u² = 2as

Answer 2

QuestioN :

A  truck travelling at 54 km/h is slow down to 36 km/h in 10 seconds find the retardation​

GiveN :

• truck travelling speed = 54 km/h.
• slow down to 36 km/h in 10 seconds.

To FiNd :

• The retardation​

ANswer :

The retardation​ is 0.5 m/s².

SolutioN :

We have,

$\sf Initial \:velocity,\: u = 54 m/s$

$\sf \implies [ 54 \times \dfrac{5}{18} ]\:m/s$

$\sf \implies15 m/s$

$\sf Final\: velocity, \:v = 36\: m/s$

$\sf \implies ( 36 \times \dfrac{5}{18} )\: m/s$

$\sf \implies 10 m/s$

$\sf Time, \:t = 10\: sec$

We know that,

$\sf Acceleration, \:a = \dfrac{( v - u )}{t}$

$\sf \implies \dfrac{ ( 10- 15 )}{ 10}$

$\sf \implies \dfrac{- 5 }{10}$

$\sf \implies \dfrac{- 1}{ 2}$

$\sf \implies - 0.5 m/s^2$

∴Hence, the retardation = 0.5 m/s².

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