Question

A truck travelling with a velocity of 30 metre per second come to rest after 10 seconds calculate its acceleration

Answer 1

Answer:

Given Final velocity (v) = 50 m/s

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.5

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520 = t or 8 = t

Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520 = t or 8 = t∴ Time taken to accelerate = 8 seconds

Answer 2

ANSWER:

5m/s

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