a truck travels 25km north and 50km in direction 60degree west of north find the magnitude and direction of the truck resultant displacement
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Given:
The north distance is 25 Km
The other distance is 50 Km
The angle is 60
To find:
The resultant displacement.
Solution:
The distance 50 in components be 50.cos30
The total displacement is
=25i+25i+(-50.cos30j)
=50i-50.cosj
Now the resultant displacement
50² + (43.30)²
=66.143
The resultant displacement is 66.143
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