Question

A truck uniformly accelerates to 0.6 m/sec² for 10 sec. If truck started from rest, determine the distance travel for this duration and its final velocity also.​

Answer 1

• initial velocity=u=0m/s
• Acceleration=0.6m/s^2=a
• Time=t=10s
• distance=s
• Final velocity=v

Using first equation of kinematics

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=0+0.6(10)$

$\\ \sf\longmapsto v=6m/s$

USING second equation of kinematics

$\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf\longmapsto s=0(10)+\dfrac{1}{2}\times 0.6(10)$

$\\ \sf\longmapsto s=\dfrac{6}{2}$

$\\ \sf\longmapsto s=3m$