Question

A truck weighing 1000 kg changes its speed from 36km h to 72 km h in 2 minutes. Calculate the work done by the engine and its power

Answer 1

We know that 1 Km/h = 5/18 m/sec.

That is 36 Km/h = 10 m/sec and 72 Km/h = 20 m/sec.

K.E=0.5mv

2

For work done by the engine we need to take the difference i.e

W=0.5×100×(20

2

−10

2

)J

W=1.5×10

4

J.