a truck weighing 1050 kgf changes its speed from 36 km/hr to 72 km/hr in 2 min.find the work done by the engine and its power
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72 kmph = 20 m/s
36 kmph = 10 m/s
Work done = Change in kinetic energy
= 0.5m (v^2 - u^2)
= 0.5 × 1050 × (20^2 - 10^2)
= 157500 J
= 157.5 kJ
Power = Work / Time
= 157500 J / (2 × 60 s)
= 1312.5 watts
= 1.3125 kW
36 kmph = 10 m/s
Work done = Change in kinetic energy
= 0.5m (v^2 - u^2)
= 0.5 × 1050 × (20^2 - 10^2)
= 157500 J
= 157.5 kJ
Power = Work / Time
= 157500 J / (2 × 60 s)
= 1312.5 watts
= 1.3125 kW
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