Accountancy, asked by CHATURVEDIAYUSHI789, 11 hours ago

A trust fund has Rs. 30,000 that must be invested in two different types of bonds. The first bond pays 5% interest per year, and the second bond pays 7% interest per year. Using matrix multiplication, determine how to divide Rs. 30,000 among the two types of bonds. If the trust fund must obtain an annual total interest of
A) Rs. 1800 . B) Rs. 2000​

Answers

Answered by mathdude500
3

\large\underline{\sf{Solution-}}

Let assume that

Amount invested in first type of bond be Rs x

Amount invested in second type of bond be Rs (30000 - x)

Given that, The first bond pays 5 % interest per annum and second one pays 7% interest per annum.

So, matrix form of the above data is as

\sf \: A = \bigg[ \begin{matrix}x& 30000 - x  \end{matrix} \bigg] \\  \\

B = \left[\begin{array}{c}  \dfrac{5}{100} \\  \\ \dfrac{7}{100} \end{array}\right] \\  \\

Given that,

\sf \: Interest\:received \:  = \:  Rs \: 1800 \\  \\

\sf \: AB \:  = \:[ 1800] \\  \\

\sf \: \bigg[ \begin{matrix}x& 30000 - x  \end{matrix} \bigg]\left[\begin{array}{c}  \dfrac{5}{100} \\  \\ \dfrac{7}{100} \end{array}\right] = [ 1800] \\  \\

\sf\: \left[x \times \dfrac{5}{100} + (30000 - x) \times \dfrac{7}{100}   \right] = [ 1800] \\  \\

\sf\: \left[ \dfrac{5x + 210000 - 7x}{100}  \right] = [ 1800] \\  \\

\sf\: \left[ \dfrac{210000 - 2x}{100}  \right] = [ 1800] \\  \\

\sf \: 210000 - 2x = 180000 \\  \\

\sf \:  2x = 210000 - 180000 \\  \\

\sf \:  2x = 30000 \\  \\

\implies\sf \: x = 15000 \\  \\

Thus,

\implies\sf \: Investment\:in\:first\:bond= Rs \: 15000 \\  \\

and

\implies\sf \: Investment\:in\:second\:bond = Rs \: 15000 \\  \\

Given that,

\sf \: Interest\:received \:  = \:  Rs \: 2000 \\  \\

\sf \: AB \:  = \:[ 2000] \\  \\

\sf \: \bigg[ \begin{matrix}x& 30000 - x  \end{matrix} \bigg]\left[\begin{array}{c}  \dfrac{5}{100} \\  \\ \dfrac{7}{100} \end{array}\right] = [ 2000] \\  \\

\sf\: \left[x \times \dfrac{5}{100} + (30000 - x) \times \dfrac{7}{100}   \right] = [ 2000] \\  \\

\sf\: \left[ \dfrac{5x + 210000 - 7x}{100}  \right] = [ 2000] \\  \\

\sf\: \left[ \dfrac{210000 - 2x}{100}  \right] = [ 2000] \\  \\

\sf \: 210000 - 2x = 200000 \\  \\

\sf \:  2x = 210000 - 200000 \\  \\

\sf \:  2x = 10000 \\  \\

\implies\sf \: x = 5000 \\  \\

Thus,

\implies\sf \: Investment\:in\:first\:bond= Rs \: 5000 \\  \\

and

\implies\sf \: Investment\:in\:second\:bond = Rs \: 25000 \\  \\

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