Question

A tube length L and radius R is joined to another tube of length 1/3 and radius
R/2. A fluid is flowing through this joint tube. If the pressure difference across the
first tube is 'P'. Then pressure difference across the second tube is
A) 16P/3
B) 4P/3
C) P
D) 3P/16​

Answer 1

Explanation:

P = 1/2 d x v^2 (Bernoulli eqn)

d= density

v= velocity

To compare the velocities, use A1v1 = A2v2 (eqn of continuity)

A1,A2 = areas

Try else tell in comments