Physics, asked by rkvgmailcom8175, 1 year ago

A tube open at both ends has fundamental frequency n . If one end of tube is dipped in water to half of its length what would be its fundamental frequency

Answers

Answered by lucky5072
4

For open end pipe in air, fundamental frequency:

f = V/2L

For the pipe closed at one end (dipped in water), fundamental frequency:

f' = V/4L'

L' = L/2

f' = V/2L = f

The correct option is C.

Answered by SahittiNerkar
0

Fundamental frequency of a tube open at both ends =(v÷2l)

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