A tube open at both ends has fundamental frequency n . If one end of tube is dipped in water to half of its length what would be its fundamental frequency
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4
For open end pipe in air, fundamental frequency:
f = V/2L
For the pipe closed at one end (dipped in water), fundamental frequency:
f' = V/4L'
L' = L/2
f' = V/2L = f
The correct option is C.
Answered by
0
Fundamental frequency of a tube open at both ends =(v÷2l)
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