Question

A tube open at both ends has fundamental frequency 'n'. If one end of the tube is dipped in water to half of its length, what would be its fundamental frequency ?

Answer 1

For open end organ pipe in air,

fundamental frequency is given by f = V/2L....(1)

where V is speed of sound and L is length of organ pipe.

when open organ pipe is dipped in water to half of its length , it changes into closed organ pipe and we know, fundamental frequency of closed organ pipe is given by f' = V/4L'

here L' = half of open organ pipe = L/2

so, f' = V/4(L/2) = V/2L = f [ from equation (1) ]

hence, fundamental frequency will be f.

Answer 2

Answer:

For open end organ pipe in air,

fundamental frequency is given by f = V/2L....(1)

where V is speed of sound and L is length of organ pipe.

when open organ pipe is dipped in water to half of its length , it changes into closed organ pipe and we know, fundamental frequency of closed organ pipe is given by f' = V/4L'

here L' = half of open organ pipe = L/2

so, f' = V/4(L/2) = V/2L = f [ from equation (1) ]

hence, fundamental frequency will be f.