Question

A tuning fork is kept between two organ pipes A and B is closed at one end and is of length 18 cm while organ pipe and first overtone of pipe are in resonance with tuning fork, then the length of open organ pipe​

Answer 1

Answer:

Explanation:

​

 

1

​

=ν  

2

​

 

4l  

1

​

 

3v

​

=  

2l  

2

​

 

4v

​

 

 

l  

2

​

 

l  

1

​

 

​

=  

8

3

​

Answer 2

Answer:

Therefore, length of an open organ pipe is 8.

Explanation:

Because both pipes are in resonance with the same tuning fork, they will vibrate at the same frequency.

For an organ pipe with one end closed,

First overtone ( n = 3 )

f = $\frac{3v}{4l_{1} }$ -------(1)

For organ pipe open at both ends,

Third overtone ( n=4 ),

$f = \frac{4v}{2l_{2} }$ --------(2)

From (1) and (2),

$\frac{3v}{4l_{1} } = \frac{4v}{2l_{2} }$

⇒ $\frac{l_{1} }{l_{2} } = \frac{3}{8}$

So, length of an open organ pipe is 8.

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