a tuning fork is kept between two organ pipes A and B. Organ pipe A is closed at one end and is of length 18cm while organ pipe B is opened at both ends as shown in the figure if fourth overtone of pipe B and first overtone of pipe A are in resonance with the tuning fork the length of organ pipe B is
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Answer:
First overtone of closed organ pipe:
4
3λ
=L
1
f
1
=
λ
1
v
=
4L
1
3v
Third overtone of open organ pipe:
2
4λ
=L2
f2
= λ 2v
= L2
2v
Given f1
=f2
4L1
3v
= L2
2v
⇒ L2
L 1
= 8/3
Explanation:
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