Question

A tuning fork makes 500 vibration in 10 second. Calculate it's frequency and time period.
please give me full solution and write answer.​

Answer 1

Answer:

Hey There!

A tuning fork makes 500 vibration in 10 second...

In one second it will be

$\frac{50 \cancel{0}}{1 \cancel{0}}$

It is 50 vibration/second or frequency.

Now time period it will be

$\frac{1}{50}$

It will be 1/50 seconds or 0.004 seconds

$\Large\textsf{Hope \: It \: Helped}$

Answer 2

Given:    no. of vibrations=500

               time interval= 10 seconds

To find:  frequency and time period.

solutions:

As, we know that,

No. of vibrations  per second = 500/2 = 250 Hz

So, Frequency of the tuning fork is 250 Hz.

Time period for one vibrations ( oscillations )  = 1 /frequency

                                                                            = 1/250 sec.

So, Time period for one vibrations ( oscillations ) = 1/250 sec.