Question

A tuning fork of frequency of 300Hz and another tuning fork of unknown frequency are vibrated together. if they produce 10 beats in one second,the time interval between two consecutive beats is​

Answer 1

first we have to find the frequency of the second tuning fork

and we know that beat=F2-F1

beat frequency=10hz

10=x-300

x=310hz

period of vibration is 1/f

T=1/10

T=0.1s

So the time interval is 0.1s

Answer 2

As we learnt in

Property of stationary waves -

1) Disturbance do not move in any direction.

2) All particles except nodes perform S.H.M.

3) During the formation of a stationary wave the medium is broken into equally spaced loops

4) Amplitude of the particle is different at different point

brain list please