Question

A tuning fork originally in unison with another fork of frequency 260 produces 4 beats per second when a little wax is attached to it. What is the frequency now?

Answer 1

Given:

A tuning fork originally in unison with another fork of frequency 260 produces 4 beats per second when a little wax is attached to it.  

To find:

What is the frequency now?

Solution:

From given, we have,

A tuning fork originally in unison with another fork of frequency 260 produces 4 beats per second when a little wax is attached to it.  

The original frequency = f1 = 260 Hz

Number of beats per second = n = 4

Therefore, the new frequency should be less than the original frequency, as the frequency decreases with the attached wax.

The new frequency = f2 = f1 - n

f2 = 260 - 4

∴ The new frequency = 256 Hz