Question

A tuning fork produces 3 beats per second when sounded together with a fork of frequency is 364 Hz. When the first fork is loaded with a little wax then the number of beats becomes two per second .What is the frequency of the first fork?

Answer 1

Answer:

Explanation:

Hello dear,

Answer- 252 Hz

Explaination-

Given-

n1 = 256 Hz

n2 = unknown

b1 = 4 Hz

b2 = 6 Hz

# Solution-

Initially,

n2 = n1 + b or n1 - b

n2 = 256 + 4 or 256 - 4

n2 = 260 Hz or 252 Hz

After putting wax, frequency of tuning fork will decrease. n2' < n2 .

(I) Taking n2 = 260 ,

n2' = 256 + 6 = 262 Hz

Here, n2' > n2 which is not the case in added wax.

(II) Taking n2 = 252 Hz,

n2' = 256 - 6 = 250 Hz

Here, n2' < n2 ,which is the case for wax adding.

Hope this is useful..

Answer 2

Solution is attached above .....