A tuning fork produces sound of frequency 200 Hz. Find the time period of vibration.
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16
Answer:
Frequency = 200 Hz, speed of sound = 330 m/s, number of vibrations = 20. Therefore, time period = 1/200 = 0.005 s.
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Answer:
Frequency = 200 Hz, speed of sound = 330 m/s, number of vibrations = 20. Therefore, time period = 1/200 = 0.005
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