Question

A tuning fork vibrate the frequency of 2114 times in 7 seconds find its frequency and time period ​

Answer 1

Answer:

T≈0.003 secs.

Explanation:

Since frequency of an object is the no. of times it oscillates per second,

and the tuning fork vibrates 2114 times in 7 seconds,

therefore the no. of times it vibrates in 1 second= 2114/7= 302

Hence, its frequency(v)= 302 Hz

Now, according to frequency-time relation

v=1/T(time period)

vT=1

T=1/v

On substituting,

T=1/302

T≈ 0.003 secs.

Hope this helps :)

Answer 2

Given : A tuning fork vibrate the frequency of 2114 times in 7 seconds.

　

To find : What is its time period and frequency?

　

Using formula :

1) Frequency = Number of times the pendulum oscillates/Total number of time taken.

　

2) Time period = Number of oscillation per second/Frequency.

　

Calculations :

→ Frequency = 2114/7

→ Frequency = 302 hertz

　

→ Time period = 7/302

→ Time period = 0.0231788079 seconds

　

Therefore,

1. Frequency = 302 hertz.
2. Time period = 0.0231788079 seconds.