A TUNING FORK VIBRATES 500 TIMES IN IN 45 SECONDS FIND FREQUENCY OF THE VIBRATION AND TIME PERIOD OFF THE VIBRATION
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Answer:
87.5m
f=500
T=
f
1
=
500
1
T is for 1 vibration.
∴ t for 125 vibrations in T×125
t=
500
125
d=Vt
=
500
350×125
d=87.5
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