A tuning fork vibrates 512 oscillations per seconds. Find the time period of the vibrations produced and its frequency.
Answers
Answered by
0
Answer:
336m/s
Explanation:
The distance traveled for one vibration is equal to the wavelength. So 64λ=42
∴λ= 42/64
=0.656
Velocity of sound v=λν=0.656×512=336m/s
Answered by
1
Answer:
Given- The frequency of the vibration is f=512 Hz f = 512 Hz . Thus, the period of vibration is 1.95 milliseconds
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