Question

A turbine develops 500 kw power under a head of 100 m at 200 rpm. What would be its normal speed under a head of 81 m?

Answer 1

Explanation:

Given  

A turbine develops 500 kw power under a head of 100 m at 200 rpm. What would be its normal speed under a head of 81 m?  

• Given P1 = 500 KW  
• H1 = 100 m
• H2 = 81 m
• N1 = 200 rpm
• N2 = ?
• So h ∝ N^2
• H1 / N1^2 = H2 / N2^2
• So N2^2 = N1^2 x H2 / H1
•               = 200 ^2 x 81 / 100
•              = 400 x 81
• So N2 = √400 x 81
•           = 20 x 9
•          = 180 rpm

Therefore N2 = 180 rpm

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