Question

A turn of radius 100 m is being designed for a speed of 25 m/s. At what angle should the turn be banked?

Answer correctly

Answer 1

Answer:

The angle of banking is given by θ=tan^−1  (v^2  /rg). Substituting the values, we get,  θ=tan?^−1

(25^2  /100×10)=tan^−1

(0.625)=32 degrees

Answer 2

Answer:

Here, radius of turn, r = 100 m

speed of the car, v = 25 m/s

free-fall acceleration, g = 9.8 m/s2

We have to find out the bank angle, θ.

From the free body diagram of the car,

Fnet = Fcentripetal

mg tanθ = mv2/r

tanθ = v2/rg

θ = tan-1(v2/rg)

= tan-1 [(25 m/s)2/ (100 m) (9.8 m/s2)] = 33º

So, the banking angle should be about 33º.