Question

A turtle and a snail are 200 feet apart when they start moving towards each other. The turtle is moving at a speed of T feet per minute, and the snail is moving at a speed of S feet per minute.
a
How fast are they approaching each other?

Answer 1

Given:

Distance between turtle and snail=200 feet

Speed of turtle=T ft/min

Speed of Snail=S ft/min

To find:

Let time=t

After t min they will meet to each other.

We know that

$Distance=Speed\times time$

Using the formula

Distance covered by turtle in time t=Tt ft

Distance covered by snail in time t=St ft

According to question

$Tt+St=200$

$t(T+S)=200$

$t=\frac{200}{T+S}min$

Time taken by  them in approaching to each other = 200/T+S min